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Statement List for Metamath Proof Explorer - 6601-6700 - Page 67 of 107
TypeLabelDescription
Statement
 
Theoremsq01t 6601 If a complex number equals its square, it must be 0 or 1.
(A ∈ ℂ → ((A↑2) = A ↔ (A = 0 ⋁ A = 1)))
 
Theorembernneq 6602 Bernoulli's inequality, due to Johan Bernoulli (1667-1748).
((A ∈ ℝ ⋀ N ∈ ℕ0 ⋀ -1 ≤ A) → (1 + (A · N)) ≤ ((1 + A)↑N))
 
Theorembernneq2 6603 Variation of Bernoulli's inequality bernneq 6602.
((A ∈ ℝ ⋀ N ∈ ℕ0 ⋀ 0 ≤ A) → (((A − 1) · N) + 1) ≤ (AN))
 
Theoremexpnbndt 6604 Exponentiation with a mantissa greater than 1 has no upper bound.
((A ∈ ℝ ⋀ B ∈ ℝ ⋀ 1 < B) → ∃k ∈ ℕ A < (Bk))
 
Discriminant
 
Theoremdiscrlem1 6605 Lemma for discriminant theorem.
 
Theoremdiscrlem2 6606 Lemma for discriminant theorem.
 
Theoremdiscrlem3 6607 Lemma for discriminant theorem.
 
Theoremdiscrlem 6608 If a quadratic polynomial with real coefficients is nonnegative for all values, then its discriminant is non-positive. The antecedent 0 ≤ A is redundant but simplifies the proof.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   x ∈ ℝ 0 ≤ (((A · (x↑2)) + (B · x)) + C)    ⇒   (0 ≤ A → ((B↑2) − (4 · (A · C))) ≤ 0)
 
More natural number properties
 
Theoremnnsqcl 6609 The square of a natural number is a natural number.
N ∈ ℕ    ⇒   (N↑2) ∈ ℕ
 
Theoremnnlesq 6610 A natural number is less than or equal to its square.
N ∈ ℕ    ⇒   N ≤ (N↑2)
 
Theoremnnesq 6611 A natural number is even iff its square is even.
N ∈ ℕ    ⇒   ((N / 2) ∈ ℕ ↔ ((N↑2) / 2) ∈ ℕ)
 
Ordered pair theorem for nonnegative integers
 
Theoremnn0le2msqt 6612 The square function on nonnegative integers is monotonic. (Contributed by Raph Levien, 10-Dec-2002.)
A ∈ ℕ0    &   B ∈ ℕ0    ⇒   (AB ↔ (A · A) ≤ (B · B))
 
Theoremnn0opthlem1 6613 A rather pretty lemma for nn0opth 6615. (Contributed by Raph Levien, 10-Dec-2002.)
A ∈ ℕ0    &   C ∈ ℕ0    ⇒   (A < C ↔ ((A · A) + (2 · A)) < (C · C))
 
Theoremnn0opthlem2 6614 Lemma for nn0opth 6615.
 
Theoremnn0opth 6615 An ordered pair theorem for nonnegative integers. Theorem 17.3 of [Quine] p. 124. We can represent an ordered pair of nonnegative integers A and B by (((A + B) · (A + B)) + B). If two such ordered pairs are equal, their first elements are equal and their second elements are equal. Contrast this ordered pair representation with the standard one df-op 2412 that works for any set. (Contributed by Raph Levien, 10-Dec-2002.)
A ∈ ℕ0    &   B ∈ ℕ0    &   C ∈ ℕ0    &   D ∈ ℕ0    ⇒   ((((A + B) · (A + B)) + B) = (((C + D) · (C + D)) + D) ↔ (A = CB = D))
 
Theoremnn0opth2 6616 An ordered pair theorem for nonnegative integers. Theorem 17.3 of [Quine] p. 124. See nn0opth 6615.
A ∈ ℕ0    &   B ∈ ℕ0    &   C ∈ ℕ0    &   D ∈ ℕ0    ⇒   ((((A + B)↑2) + B) = (((C + D)↑2) + D) ↔ (A = CB = D))
 
Theoremnn0opth2t 6617 An ordered pair theorem for nonnegative integers. Theorem 17.3 of [Quine] p. 124. See nn0opth 6615.
(((A ∈ ℕ0B ∈ ℕ0) ⋀ (C ∈ ℕ0D ∈ ℕ0)) → ((((A + B)↑2) + B) = (((C + D)↑2) + D) ↔ (A = CB = D)))
 
Square root
 
Syntaxcsqr 6618 Extend class notation to include positive square root of a positive real number.
class
 
Definitiondf-sqr 6619 Define a function whose value is the square root of a nonnegative real number. The square root of x is the supremum of all reals whose square is less than x. See sqrcl 6649 for its closure, sqrval 6620 for its value, sqrsq 6669 and sqsqr 6670 for its relationship to squares, and sqr11 6652 for uniqueness.
√ = {⟨x, y⟩∣((x ∈ ℝ ⋀ 0 ≤ x) ⋀ y = sup({z ∈ ℝ∣(0 ≤ z ⋀ (z · z) ≤ x)}, ℝ, < ))}
 
Theoremsqrval 6620 Value of square root function.
((A ∈ ℝ ⋀ 0 ≤ A) → (√ ‘A) = sup({x ∈ ℝ∣(0 ≤ x ⋀ (x · x) ≤ A)}, ℝ, < ))
 
Theoremsqr0 6621 Square root of zero.
(√ ‘0) = 0
 
Theoremsqrlem1 6622 Lemma for square root theorem.
 
Theoremsqrlem2 6623 Lemma for square root theorem.
 
Theoremsqrlem3 6624 Lemma for square root theorem.
 
Theoremsqrlem4 6625 Lemma for square root theorem.
 
Theoremsqrlem5 6626 Lemma for square root theorem.
 
Theoremsqrlem6 6627 Lemma for square root theorem.
 
Theoremsqrlem7 6628 Lemma for square root theorem.
 
Theoremsqrlem8 6629 Lemma for square root theorem.
 
Theoremsqrlem9 6630 Lemma for square root theorem.
 
Theoremsqrlem10 6631 Lemma for square root theorem.
 
Theoremsqrlem11 6632 Lemma for square root theorem.
 
Theoremsqrlem12 6633 Lemma for square root theorem.
 
Theoremsqrlem13 6634 Lemma for square root theorem.
 
Theoremsqrlem14 6635 Lemma for square root theorem.
 
Theoremsqrlem15 6636 Lemma for square root theorem.
 
Theoremsqrlem16 6637 Lemma for square root theorem.
 
Theoremsqrlem17 6638 Lemma for square root theorem.
 
Theoremsqrlem18 6639 Lemma for square root theorem.
 
Theoremsqrlem19 6640 Lemma for square root theorem.
 
Theoremsqrlem20 6641 Lemma for square root theorem.
 
Theoremsqrlem21 6642 Lemma for square root theorem.
 
Theoremsqrlem22 6643 Lemma for square root theorem.
 
Theoremsqrlem23 6644 Lemma for square root theorem.
 
Theoremsqrlem24 6645 Lemma for square root closure.
 
Theoremsqrgt0i 6646 The square root of a positive real is positive.
A ∈ ℝ    &   0 < A    ⇒   0 < (√ ‘A)
 
Theoremsqrlem26 6647 Lemma for square root theorem.
 
Theoremsqrth 6648 Square root theorem. Theorem I.35 of [Apostol] p. 29.

(A bit of trivia: This theorem was added to the database before the number 2 was defined and before exponents were defined. Thus you will see (1 + 1) and (x · x) throughout its lemmas.)

A ∈ ℝ    ⇒   (0 ≤ A → ((√ ‘A) · (√ ‘A)) = A)
 
Theoremsqrcl 6649 The square root of a nonnegative real is a real.
A ∈ ℝ    ⇒   (0 ≤ A → (√ ‘A) ∈ ℝ)
 
Theoremsqrgt0 6650 The square root of a positive real is positive.
A ∈ ℝ    ⇒   (0 < A → 0 < (√ ‘A))
 
Theoremsqrge0 6651 The square root of a nonnegative real is nonnegative.
A ∈ ℝ    ⇒   (0 ≤ A → 0 ≤ (√ ‘A))
 
Theoremsqr11 6652 The square root function is one-to-one.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ⋀ 0 ≤ B) → ((√ ‘A) = (√ ‘B) ↔ A = B))
 
Theoremsqrmuli 6653 Square root distributes over multiplication.
A ∈ ℝ    &   B ∈ ℝ    &   0 ≤ A    &   0 ≤ B    ⇒   (√ ‘(A · B)) = ((√ ‘A) · (√ ‘B))
 
Theoremsqrmul 6654 Square root distributes over multiplication.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ⋀ 0 ≤ B) → (√ ‘(A · B)) = ((√ ‘A) · (√ ‘B)))
 
Theoremsqrmsq2 6655 Relationship between square root and squares.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ⋀ 0 ≤ B) → ((√ ‘A) = BA = (B · B)))
 
Theoremsqrle 6656 Square root is monotonic.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ⋀ 0 ≤ B) → (AB ↔ (√ ‘A) ≤ (√ ‘B)))
 
Theoremsqrlt 6657 Square root is strictly monotonic. (Contributed by Roy F. Longton, 8-Aug-2005.)
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ⋀ 0 ≤ B) → (A < B ↔ (√ ‘A) < (√ ‘B)))
 
Theoremsqrmsq 6658 Square root of square.
A ∈ ℝ    ⇒   (0 ≤ A → (√ ‘(A · A)) = A)
 
Theoremsqrclt 6659 The square root of a nonnegative real is a real.
((A ∈ ℝ ⋀ 0 ≤ A) → (√ ‘A) ∈ ℝ)
 
Theoremsqrgt0t 6660 The square root of a positive real is positive.
((A ∈ ℝ ⋀ 0 < A) → 0 < (√ ‘A))
 
Theoremsqrge0t 6661 The square root of a nonnegative real is nonnegative.
((A ∈ ℝ ⋀ 0 ≤ A) → 0 ≤ (√ ‘A))
 
Theoremsqrlet 6662 Square root is monotonic.
(((A ∈ ℝ ⋀ B ∈ ℝ) ⋀ (0 ≤ A ⋀ 0 ≤ B)) → (AB ↔ (√ ‘A) ≤ (√ ‘B)))
 
Theoremsqr00t 6663 A square root is zero iff its argument is 0.
((A ∈ ℝ ⋀ 0 ≤ A) → ((√ ‘A) = 0 ↔ A = 0))
 
Theoremrpsqrclt 6664 The square root of a positive real is a postive real.
(A ∈ ℝ+ → (√ ‘A) ∈ ℝ+)
 
Theoremsqr1 6665 The square root of 1 is 1.
(√ ‘1) = 1
 
Theoremsqr4 6666 The square root of 4 is 2.
(√ ‘4) = 2
 
Theoremsqr9 6667 The square root of 9 is 3.
(√ ‘9) = 3
 
Theoremsqr2gt1lt2 6668 The square root of 2 is bounded by 1 and 2. (Contributed by Roy F. Longton, 8-Aug-2005.)
(1 < (√ ‘2) ⋀ (√ ‘2) < 2)
 
Theoremsqrsq 6669 Square root of square.
A ∈ ℝ    ⇒   (0 ≤ A → (√ ‘(A↑2)) = A)
 
Theoremsqsqr 6670 Square of square root.
A ∈ ℝ    ⇒   (0 ≤ A → ((√ ‘A)↑2) = A)
 
Theoremsqrsqt 6671 Square root of square.
((A ∈ ℝ ⋀ 0 ≤ A) → (√ ‘(A↑2)) = A)
 
Theoremsqsqrt 6672 Square of square root.
((A ∈ ℝ ⋀ 0 ≤ A) → ((√ ‘A)↑2) = A)
 
Irrationality of square root of 2
 
Theoremsqr2irrlem1 6673 Lemma for irrationality of square root of 2. Technical lemma used to simplify the main induction step.
 
Theoremsqr2irrlem2 6674 Lemma for irrationality of square root of 2. Eliminates hypotheses with weak deduction theorem.
 
Theoremsqr2irrlem3 6675 Main theorem for irrationality of square root of 2. There are no natural numbers such that the square of one is twice the square of the other. Uses strong induction.
¬ ∃x ∈ ℕ ∃y ∈ ℕ (x↑2) = (2 · (y↑2))
 
Theoremsqr2irrlem4 6676 Lemma for irrationality of square root of 2.
 
Theoremsqr2irrlem5 6677 Lemma for irrationality of square root of 2. Eliminates hypotheses with weak deduction theorem.
 
Theoremsqr2irr 6678 The square root of 2 is irrational.
(√ ‘2) ∉ ℚ
 
Theoremsqr2re 6679 The square root of 2 exists and is a real number.
(√ ‘2) ∈ ℝ
 
Imaginary and complex number properties
 
Theoremirec 6680 The reciprocal of i.
(1 / i) = -i
 
Theoremi2 6681 i squared.
(i↑2) = -1
 
Theoremi3 6682 i cubed.
(i↑3) = -i
 
Theoremi4 6683 i to the fourth power.
(i↑4) = 1
 
Theoreminelr 6684 The imaginary unit i is not a real number.
¬ i ∈ ℝ
 
Theoremcrulem 6685 Lemma for cru 6686.
 
Theoremcru 6686 The representation of complex numbers in terms of real and imaginary parts is unique. Proposition 10-1.3 of [Gleason] p. 130.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   D ∈ ℝ    ⇒   ((A + (i · B)) = (C + (i · D)) ↔ (A = CB = D))
 
Theoremcrut 6687 The representation of complex numbers in terms of real and imaginary parts is unique. Proposition 10-1.3 of [Gleason] p. 130.
(((A ∈ ℝ ⋀ B ∈ ℝ) ⋀ (C ∈ ℝ ⋀ D ∈ ℝ)) → ((A + (i · B)) = (C + (i · D)) ↔ (A = CB = D)))
 
TheoremcrutOLD 6688 The representation of complex numbers in terms of real and imaginary parts is unique. Proposition 10-1.3 of [Gleason] p. 130.
(((A ∈ ℝ ⋀ B ∈ ℝ) ⋀ (C ∈ ℝ ⋀ D ∈ ℝ)) → ((A + (B · i)) = (C + (D · i)) ↔ (A = CB = D)))
 
Theoremcrne0 6689 The real representation of complex numbers is nonzero iff one of its terms is nonzero.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((A ≠ 0 ⋁ B ≠ 0) ↔ (A + (i · B)) ≠ 0)
 
Theoremcrmul 6690 Multiplication rule for complex number representation. Remark in [Apostol] p. 361. In normal use, the arguments are the real components of two complex numbers, but the theorem works for complex components as well.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    &   D ∈ ℂ    ⇒   ((A + (i · B)) · (C + (i · D))) = (((A · C) − (B · D)) + (i · ((A · D) + (B · C))))
 
Theoremcrrecz 6691 Reciprocal of a complex number in terms of real and imaginary components. Remark in [Apostol] p. 361.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((A ≠ 0 ⋁ B ≠ 0) → (1 / (A + (i · B))) = ((A − (i · B)) / ((A↑2) + (B↑2))))
 
Theoremcreur 6692 The real part of a complex number is unique. Proposition 10-1.3 of [Gleason] p. 130.
(A ∈ ℂ → ∃!x ∈ ℝ ∃y ∈ ℝ A = (x + (i · y)))
 
Theoremcreui 6693 The imaginary part of a complex number is unique. Proposition 10-1.3 of [Gleason] p. 130.
(A ∈ ℂ → ∃!y ∈ ℝ ∃x ∈ ℝ A = (x + (i · y)))
 
Theoremrimul 6694 A real number times the imaginary unit is real only if the number is 0.
((A ∈ ℝ ⋀ (i · A) ∈ ℝ) → A = 0)
 
Theoremnthruc 6695 The sequence ℕ, ℤ, ℚ, ℝ, and ℂ forms a chain of proper subsets. In each case the proper subset relationship is shown by demonstrating a number that belongs to one set but not the other. We show that zero belongs to ℤ but not ℕ, one-half belongs to ℚ but not ℤ, the square root of 2 belongs to ℝ but not ℚ, and finally that the imaginary number i belongs to ℂ but not ℝ. See nthruz 6696 for a further refinement.
((ℕ ⊂ ℤ ⋀ ℤ ⊂ ℚ) ⋀ (ℚ ⊂ ℝ ⋀ ℝ ⊂ ℂ))
 
Theoremnthruz 6696 The sequence ℕ, ℕ0, and ℤ forms a chain of proper subsets. In each case the proper subset relationship is shown by demonstrating a number that belongs to one set but not the other. We show that zero belongs to ℕ0 but not ℕ and minus one belongs to ℤ but not ℕ0. This theorem refines the chain of proper subsets nthruc 6695.
(ℕ ⊂ ℕ0 ⋀ ℕ0 ⊂ ℤ)
 
Real and imaginary parts; conjugate; absolute value
 
Syntaxcre 6697 Extend class notation to include real part of a complex number.
class
 
Syntaxcim 6698 Extend class notation to include imaginary part of a complex number.
class
 
Syntaxccj 6699 Extend class notation to include complex conjugate function.
class
 
Syntaxcabs 6700 Extend class notation to include a function for the absolute value (modulus) of a complex number.
class abs

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