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Theorem difin0ss 2342
Description: Difference, intersection, and subclass relationship.
Assertion
Ref Expression
difin0ss (((A B) ∩ C) = → (C AC B))

Proof of Theorem difin0ss
StepHypRef Expression
1 eq0 2304 . . 3 (((A B) ∩ C) = x ¬ x ((A B) ∩ C))
2 annim 238 . . . . . . . . 9 ((x A ¬ x B) ↔ ¬ (x Ax B))
32anbi2i 483 . . . . . . . 8 ((x C (x A ¬ x B)) ↔ (x C ¬ (x Ax B)))
4 ancom 438 . . . . . . . 8 ((x C (x A ¬ x B)) ↔ ((x A ¬ x B) x C))
53, 4bitr3 175 . . . . . . 7 ((x C ¬ (x Ax B)) ↔ ((x A ¬ x B) x C))
65negbii 187 . . . . . 6 (¬ (x C ¬ (x Ax B)) ↔ ¬ ((x A ¬ x B) x C))
7 iman 237 . . . . . 6 ((x C → (x Ax B)) ↔ ¬ (x C ¬ (x Ax B)))
8 elin 2216 . . . . . . . 8 (x ((A B) ∩ C) ↔ (x (A B) x C))
9 eldif 2066 . . . . . . . . 9 (x (A B) ↔ (x A ¬ x B))
109anbi1i 484 . . . . . . . 8 ((x (A B) x C) ↔ ((x A ¬ x B) x C))
118, 10bitr 173 . . . . . . 7 (x ((A B) ∩ C) ↔ ((x A ¬ x B) x C))
1211negbii 187 . . . . . 6 x ((A B) ∩ C) ↔ ¬ ((x A ¬ x B) x C))
136, 7, 123bitr4 183 . . . . 5 ((x C → (x Ax B)) ↔ ¬ x ((A B) ∩ C))
14 ax-2 5 . . . . 5 ((x C → (x Ax B)) → ((x Cx A) → (x Cx B)))
1513, 14sylbir 201 . . . 4 x ((A B) ∩ C) → ((x Cx A) → (x Cx B)))
161519.20ii 1001 . . 3 (x ¬ x ((A B) ∩ C) → (x(x Cx A) → x(x Cx B)))
171, 16sylbi 199 . 2 (((A B) ∩ C) = → (x(x Cx A) → x(x Cx B)))
18 dfss2 2067 . 2 (C Ax(x Cx A))
19 dfss2 2067 . 2 (C Bx(x Cx B))
2017, 18, 193imtr4g 556 1 (((A B) ∩ C) = → (C AC B))
Colors of variables: wff set class
Syntax hints:  ¬ wn 2   → wi 3   wa 223  wal 958   = wceq 960   wcel 962   cdif 2053   ∩ cin 2055   wss 2056  c0 2289
This theorem is referenced by:  tz7.7 2987  tfi 3140
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 966  ax-gen 967  ax-8 968  ax-10 970  ax-12 972  ax-17 975  ax-4 977  ax-5o 979  ax-6o 982  ax-9o 1129  ax-10o 1146  ax-16 1216  ax-11o 1224  ax-ext 1466
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 985  df-sb 1178  df-clab 1471  df-cleq 1476  df-clel 1479  df-ne 1594  df-v 1819  df-dif 2058  df-in 2060  df-ss 2062  df-nul 2290
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