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Theorem sbc5g 1954
Description: An equivalence for class substitution.
Assertion
Ref Expression
sbc5g |- (A e. B -> ([A / x]ph <-> E.x(x = A /\ ph)))
Distinct variable group:   x,A

Proof of Theorem sbc5g
StepHypRef Expression
1 biimt 731 . . . . . 6 |- (A e. V -> (ph <-> (A e. V -> ph)))
21anbi2d 616 . . . . 5 |- (A e. V -> ((x = A /\ ph) <-> (x = A /\ (A e. V -> ph))))
32exbidv 1279 . . . 4 |- (A e. V -> (E.x(x = A /\ ph) <-> E.x(x = A /\ (A e. V -> ph))))
4 biimt 731 . . . 4 |- (A e. V -> (E.x(x = A /\ ph) <-> (A e. V -> E.x(x = A /\ ph))))
5 ax-17 971 . . . . . 6 |- (y e. A -> A.x y e. A)
65hbsbc1 1949 . . . . 5 |- ((A e. V -> [A / x]ph) -> A.x(A e. V -> [A / x]ph))
7 sbceq1a 1944 . . . . . 6 |- (x = A -> (ph <-> [A / x]ph))
87imbi2d 612 . . . . 5 |- (x = A -> ((A e. V -> ph) <-> (A e. V -> [A / x]ph)))
96, 8ceqsexg 1887 . . . 4 |- (A e. V -> (E.x(x = A /\ (A e. V -> ph)) <-> (A e. V -> [A / x]ph)))
103, 4, 93bitr3rd 549 . . 3 |- (A e. V -> ((A e. V -> [A / x]ph) <-> (A e. V -> E.x(x = A /\ ph))))
1110pm5.74rd 588 . 2 |- (A e. V -> (A e. V -> ([A / x]ph <-> E.x(x = A /\ ph))))
12 elisset 1817 . 2 |- (A e. B -> A e. V)
1311, 12, 12sylc 68 1 |- (A e. B -> ([A / x]ph <-> E.x(x = A /\ ph)))
Colors of variables: wff set class
Syntax hints:   -> wi 3   <-> wb 146   /\ wa 223   = wceq 956   e. wcel 958  E.wex 980  [wsbc 1170  Vcvv 1811
This theorem is referenced by:  sbc5 1956  sbc2or 1958  sbciegft 1959  sbcgf 1986  sbccomglem 1988
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 962  ax-gen 963  ax-8 964  ax-10 966  ax-12 968  ax-17 971  ax-4 973  ax-5o 975  ax-6o 978  ax-9o 1123  ax-10o 1140  ax-16 1210  ax-11o 1218  ax-ext 1459
This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 981  df-sb 1172  df-clab 1464  df-cleq 1469  df-clel 1472  df-v 1812  df-sbc 1942
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