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Statement List for Metamath Proof Explorer - 6901-7000 - Page 70 of 107
TypeLabelDescription
Statement
 
Theoremfacavgt 6901 The product of two factorials is greater than or equal to the factorial of (the floor of) their average.
|- ((M e. NN0 /\ N e. NN0) -> (!` (|_` ((M + N) / 2))) <_ ((!` M) x. (!` N)))
 
The binomial coefficient operation
 
Syntaxcbc 6902 Extend class notation to include the binomial coefficient operation (combinatorial choose operation).
class C.
 
Definitiondf-bc 6903 Define the binomial coefficient operation. In the literature, this function is often written as a column vector of the two arguments, or with the arguments as subscripts before and after the letter "C". (N C. K) is read "N choose K." Definition of binomial coefficient in [Gleason] p. 295. As suggested by Gleason, we define it to be 0 when 0 <_ k <_ n does not hold.
|- C. = {<.<.n, k>., m>. | ((n e. NN0 /\ k e. ZZ) /\ m = if((0 <_ k /\ k <_ n), ((!` n) / ((!` (n - k)) x. (!` k))), 0))}
 
Theorembcvalt 6904 Value of the binomial coefficient, N choose K. Definition of binomial coefficient in [Gleason] p. 295. As suggested by Gleason, we define it to be 0 when 0 <_ K <_ N does not hold. See bcval2t 6906 for the value in the standard domain.
|- ((N e. NN0 /\ K e. ZZ) -> (N C. K) = if((0 <_ K /\ K <_ N), ((!` N) / ((!` (N - K)) x. (!` K))), 0))
 
Theorembcval3tOLD 6905 Value of the binomial coefficient, N choose K, in its standard domain.
|- (((N e. NN0 /\ K e. ZZ) /\ (0 <_ K /\ K <_ N)) -> (N C. K) = ((!` N) / ((!` (N - K)) x. (!` K))))
 
Theorembcval2t 6906 Value of the binomial coefficient, N choose K, in its standard domain.
|- ((N e. NN0 /\ K e. NN0 /\ K <_ N) -> (N C. K) = ((!` N) / ((!` (N - K)) x. (!` K))))
 
Theorembcval3t 6907 Value of the binomial coefficient, N choose K, in its standard domain.
|- ((N e. NN0 /\ K e. (0...N)) -> (N C. K) = ((!` N) / ((!` (N - K)) x. (!` K))))
 
Theorembcval4t 6908 Value of the binomial coefficient, N choose K, outside of its standard domain. Remark in [Gleason] p. 295.
|- ((N e. NN0 /\ K e. ZZ /\ (K < 0 \/ N < K)) -> (N C. K) = 0)
 
Theorembccmplt 6909 "Complementing" its second argument doesn't change a binary coefficient.
|- ((N e. NN0 /\ K e. NN0 /\ K <_ N) -> (N C. K) = (N C. (N - K)))
 
Theorembcn0t 6910 N choose 0 is 1. Remark in [Gleason] p. 296.
|- (N e. NN0 -> (N C. 0) = 1)
 
Theorembcnnt 6911 N choose N is 1. Remark in [Gleason] p. 296.
|- (N e. NN0 -> (N C. N) = 1)
 
Theorembcnp11t 6912 Binomial coefficient: N + 1 choose 1.
|- (N e. NN0 -> ((N + 1) C. 1) = (N + 1))
 
Theorembcnp1nt 6913 Binomial coefficient: N + 1 choose N.
|- (N e. NN0 -> ((N + 1) C. N) = (N + 1))
 
Theorembcpasc2 6914 Pascal's rule for the binomial coefficient. Equation 2 of [Gleason] p. 295.
|- N e. NN   &   |- K e. NN   &   |- K <_ N   =>   |- ((N C. K) + (N C. (K - 1))) = ((N + 1) C. K)
 
Theorembcpasc2t 6915 Pascal's rule for the binomial coefficient. Equation 2 of [Gleason] p. 295.
|- ((N e. NN /\ K e. NN /\ K <_ N) -> ((N C. K) + (N C. (K - 1))) = ((N + 1) C. K))
 
Theorembcpasc 6916 Pascal's rule for the binomial coefficient, generalized to all integers K. Equation 2 of [Gleason] p. 295.
|- N e. NN0   &   |- K e. ZZ   =>   |- ((N C. K) + (N C. (K - 1))) = ((N + 1) C. K)
 
Theorembcpasct 6917 Pascal's rule for the binomial coefficient, generalized to all integers K. Equation 2 of [Gleason] p. 295.
|- ((N e. NN0 /\ K e. ZZ) -> ((N C. K) + (N C. (K - 1))) = ((N + 1) C. K))
 
Theorembccl2t 6918 A binomial coefficient, in its standard domain, is a natural number.
|- ((N e. NN0 /\ K e. (0...N)) -> (N C. K) e. NN)
 
Theorembcclt 6919 A binomial coefficient, in its extended domain, is a nonnegative integer.
|- ((N e. NN0 /\ K e. ZZ) -> (N C. K) e. NN0)
 
Theorempermnnt 6920 The number of permutations of N - R objects from a collection of N objects is a natural number. (Contributed by Jason Orendorff, 24-Jan-2007.)
|- ((N e. NN0 /\ R e. (0...N)) -> ((!` N) / (!` R)) e. NN)
 
Limits
 
Syntaxcli 6921 Extend class notation with convergence relation for limits.
class ~~>
 
Definitiondf-clim 6922 Define the limit relation for complex number sequences. See clim 6924 for its relational expression.
|- ~~> = {<.f, y>. | (y e. CC /\ A.x e. RR (0 < x -> E.j e. ZZ A.k e. ZZ (j <_ k -> ((f` k) e. CC /\ (abs` ((f` k) - y)) < x))))}
 
Theoremclimrel 6923 The limit relation is a relation.
|- Rel ~~>
 
Theoremclim 6924 Express the predicate: The limit of complex number sequence F is A, or F converges to A. This means that for any real x, no matter how small, there always exists an integer j such that the absolute difference of any later complex number in the sequence and the limit is less than x.
|- ((F e. C /\ A e. D) -> (F ~~> A <-> (A e. CC /\ A.x e. RR (0 < x -> E.j e. ZZ A.k e. ZZ (j <_ k -> ((F` k) e. CC /\ (abs` ((F` k) - A)) < x))))))
 
Theoremclimcl 6925 Closure of the limit of a sequence of complex numbers.
|- ((A e. C /\ F ~~> A) -> A e. CC)
 
Finite and infinite sums
 
Syntaxcsu 6926 Extend class notation to include finite summations. (An underscore was added the ASCII token in order to facilitate text searches, since "sum" is is a commonly used word in comments.)
class sum_k e. A B
 
Definitiondf-sum 6927 Define the sum of a series with an index set of integers A. k is normally a free variable in B, i.e. B can be thought of as B(k). The definition is meaningful when A is a finite set of sequential integers (representing a finite sum over them) or a set of upper integers (representing an infinite sum, when the sum converges). The left-hand side of the union expresses the finite sum case, and the right-hand side expresses the infinite sum case. In either case, the other side of the union equals the empty set. Examples: sum_k e. (2...4) k means 2 + 3 + 4 = 9, and sum_k e. NN (1 / (2^k)) means 1/2 + 1/4 + 1/8 + ... = 1. Note: The restrictions to ZZ force the class abstractions to be sets.
|- sum_k e. A B = ({x | E.mE.n e. (ZZ>` m)(A = (m...n) /\ x e. ((<.m, + >. seq ({<.k, y>. | y = B} |` ZZ))` n))} u. U.{x | E.m e. ZZ (A = (ZZ>` m) /\ (<.m, + >. seq ({<.k, y>. | y = B} |` ZZ)) ~~> x)})
 
Theoremsumex 6928 A sum is a set.
|- sum_k e. A B e. V
 
Theoremsumeq1 6929 Equality theorem for a sum.
|- (A = B -> sum_k e. A C = sum_k e. B C)
 
Theoremhbsum1 6930 Bound-variable hypothesis builder for sum.
|- (x e. A -> A.k x e. A)   =>   |- (x e. sum_k e. A B -> A.k x e. sum_k e. A B)
 
Theoremhbsum 6931 Bound-variable hypothesis builder for sum: if x is (effectively) not free in A and B, it is not free in sum_k e. AB.
|- (y e. A -> A.x y e. A)   &   |- (y e. B -> A.x y e. B)   =>   |- (y e. sum_k e. A B -> A.x y e. sum_k e. A B)
 
Theoremsumeq2 6932 Equality theorem for sum.
|- (A.k e. A B = C -> sum_k e. A B = sum_k e. A C)
 
Theoremcbvsum 6933 Change bound variable in a sum.
|- (x e. B -> A.k x e. B)   &   |- (x e. C -> A.j x e. C)   &   |- (j = k -> B = C)   =>   |- sum_j e. A B = sum_k e. A C
 
Theoremsumeq1i 6934 Equality inference for sum.
|- A = B   =>   |- sum_k e. A C = sum_k e. B C
 
Theoremsumeq2i 6935 Equality inference for sum.
|- (k e. A -> B = C)   =>   |- sum_k e. A B = sum_k e. A C
 
Theoremsumeq12i 6936 Equality inference for sum. (Contributed by FL, 10-Dec-2006.)
|- A = B   &   |- (k e. A -> C = D)   =>   |- sum_k e. A C = sum_k e. B D
 
Theoremsumeq1d 6937 Equality deduction for sum.
|- (ph -> A = B)   =>   |- (ph -> sum_k e. A C = sum_k e. B C)
 
Theoremsumeq2d 6938 Equality deduction for sum. Note that unlike sumeq2dv 6939, k may occur in ph.
|- (ph -> A.k e. A B = C)   =>   |- (ph -> sum_k e. A B = sum_k e. A C)
 
Theoremsumeq2dv 6939 Equality deduction for sum.
|- ((ph /\ k e. A) -> B = C)   =>   |- (ph -> sum_k e. A B = sum_k e. A C)
 
Theoremsumeq2sdv 6940 Equality deduction for sum.
|- (ph -> B = C)   =>   |- (ph -> sum_k e. A B = sum_k e. A C)
 
Theorem2sumeq2dv 6941 Equality deduction for double sum.
|- ((ph /\ j e. A /\ k e. B) -> C = D)   =>   |- (ph -> sum_j e. A sum_k e. B C = sum_j e. A sum_k e. B D)
 
Theoremsumeq12dv 6942 Equality deduction for sum.
|- (ph -> A = B)   &   |- ((ph /\ k e. A) -> C = D)   =>   |- (ph -> sum_k e. A C = sum_k e. B D)
 
Theoremsumeq12rdv 6943 Equality deduction for sum.
|- (ph -> A = B)   &   |- ((ph /\ k e. B) -> C = D)   =>   |- (ph -> sum_k e. A C = sum_k e. B D)
 
Theoremsumeqfv 6944 Convert a sum of function values to a sum of classes A(k).
|- A e. V   &   |- F = {<.k, y>. | (k e. B /\ y = A)}   =>   |- (C (_ B -> sum_k e. C (F` k) = sum_k e. C A)
 
Finite sums (cont.)
 
Theoremdffsum 6945 Special case of series sum over a finite index set.
|- (N e. (ZZ>` M) -> sum_k e. (M...N)A = ((<.M, +