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Statement List for Metamath Proof Explorer - 4401-4500 - Page 45 of 107
TypeLabelDescription
Statement
 
Theoremensymi 4401 Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92.
|- B e. V   &   |- A ~~ B   =>   |- B ~~ A
 
Theorementrt 4402 Transitivity of equinumerosity. Theorem 3 of [Suppes] p. 92.
|- ((A ~~ B /\ B ~~ C) -> A ~~ C)
 
Theoremdomtr 4403 Transitivity of dominance relation. Theorem 17 of [Suppes] p. 94.
|- ((A ~<_ B /\ B ~<_ C) -> A ~<_ C)
 
Theorementr 4404 A chained equinumerosity inference.
|- A ~~ B   &   |- B ~~ C   =>   |- A ~~ C
 
Theorementr2 4405 A chained equinumerosity inference.
|- C e. V   &   |- A ~~ B   &   |- B ~~ C   =>   |- C ~~ A
 
Theorementr3 4406 A chained equinumerosity inference.
|- B e. V   &   |- A ~~ B   &   |- A ~~ C   =>   |- B ~~ C
 
Theorementr4 4407 A chained equinumerosity inference.
|- B e. V   &   |- A ~~ B   &   |- C ~~ B   =>   |- A ~~ C
 
Theoremendomtr 4408 Transitivity of equinumerosity and dominance.
|- ((A ~~ B /\ B ~<_ C) -> A ~<_ C)
 
Theoremdomentr 4409 Transitivity of dominance and equinumerosity.
|- ((A ~<_ B /\ B ~~ C) -> A ~<_ C)
 
Theoremf1imaen 4410 A one-to-one function's image under a subset of its domain is equinumerous to the subset.
|- C e. V   =>   |- ((F:A-1-1->B /\ C (_ A) -> (F"C) ~~ C)
 
Theoremen0 4411 The empty set is equinumerous only to itself. Exercise 1 of [TakeutiZaring] p. 88.
|- (A ~~ (/) <-> A = (/))
 
Theoremensn1 4412 A singleton is equinumerous to ordinal one.
|- A e. V   =>   |- {A} ~~ 1o
 
Theoremensn1g 4413 A singleton is equinumerous to ordinal one.
|- (A e. B -> {A} ~~ 1o)
 
Theoremen1 4414 A set is equinumerous to ordinal one iff it is a singleton.
|- (A ~~ 1o <-> E.x A = {x})
 
Theorem2dom 4415 A set that dominates ordinal 2 has at least 2 different members.
|- A e. V   =>   |- (2o ~<_ A -> E.x e. A E.y e. A -. x = y)
 
Theoremfundmen 4416 A function is equinumerous to its domain. Exercise 4 of [Suppes] p. 98.
|- F e. V   =>   |- (Fun F -> dom F ~~ F)
 
Theoremmapsnen 4417 Set exponentiation to a singleton exponent is equinumerous to its base. Exercise 4.43 of [Mendelson] p. 255.
|- A e. V   &   |- B e. V   =>   |- (A ^m {B}) ~~ A
 
Theoremmap1 4418 Set exponentiation: ordinal 1 to any set is equinumerous to ordinal 1. Exercise 4.42(b) of [Mendelson] p. 255.
|- A e. V   =>   |- (1o ^m A) ~~ 1o
 
Theoremen2sn 4419 Two singletons are equinumerous.
|- ((A e. C /\ B e. D) -> {A} ~~ {B})
 
Theoremsnfi 4420 A singleton is finite.
|- E.x e. om {A} ~~ x
 
Theoremunen 4421 Equinumerosity of union of disjoint sets. Theorem 4 of [Suppes] p. 92.
|- (((A ~~ B /\ C ~~ D) /\ ((A i^i C) = (/) /\ (B i^i D) = (/))) -> (A u. C) ~~ (B u. D))
 
Theoremxpsnen 4422 A set is equinumerous to its cross-product with a singleton. Proposition 4.22(c) of [Mendelson] p. 254.
|- A e. V   &   |- B e. V   =>   |- (A X. {B}) ~~ A
 
Theoremxpsneng 4423 A set is equinumerous to its cross-product with a singleton. Proposition 4.22(c) of [Mendelson] p. 254.
|- ((A e. C /\ B e. D) -> (A X. {B}) ~~ A)
 
Theoremendisj 4424 Any two sets are equinumerous to disjoint sets. Exercise 4.39 of [Mendelson] p. 255.
|- A e. V   &   |- B e. V   =>   |- E.xE.y((x ~~ A /\ y ~~ B) /\ (x i^i y) = (/))
 
Theoremundom 4425 Dominance law for union. Proposition 4.24(a) of [Mendelson] p. 257.
|- B e. V   &   |- C e. V   &   |- D e. V   =>   |- (((A ~<_ B /\ C ~<_ D) /\ (B i^i D) = (/)) -> (A u. C) ~<_ (B u. D))
 
Theoremxpcomen 4426 Commutative law for equinumerosity of cross product. Proposition 4.22(d) of [Mendelson] p. 254.
|- A e. V   &   |- B e. V   =>   |- (A X. B) ~~ (B X. A)
 
Theoremxpcomeng 4427 Commutative law for equinumerosity of cross product. Proposition 4.22(d) of [Mendelson] p. 254.
|- ((A e. C /\ B e. D) -> (A X. B) ~~ (B X. A))
 
Theoremxpassen 4428 Associative law for equinumerosity of cross product. Proposition 4.22(e) of [Mendelson] p. 254.
|- A e. V   &   |- B e. V   &   |- C e. V   =>   |- ((A X. B) X. C) ~~ (A X. (B X. C))
 
Theoremxpdom2 4429 Dominance law for cross product. Proposition 10.33(2) of [TakeutiZaring] p. 92.
|- B e. V   &   |- C e. V   =>   |- (A ~<_ B -> (C X. A) ~<_ (C X. B))
 
Theoremxpdom1 4430 Dominance law for cross product. Theorem 6L(c) of [Enderton] p. 149.
|- B e. V   &   |- C e. V   =>   |- (A ~<_ B -> (A X. C) ~<_ (B X. C))
 
Theoremxpdom1g 4431 Dominance law for cross product. Theorem 6L(c) of [Enderton] p. 149.
|- ((B e. R /\ C e. S /\ A ~<_ B) -> (A X. C) ~<_ (B X. C))
 
Theoremxpdom3 4432 A set is dominated by its cross product with a non-empty set. Exercise 6 of [Suppes] p. 98.
|- A e. V   =>   |- (B =/= (/) -> A ~<_ (A X. B))
 
Theorempw2en 4433 The power set of a set is equinumerous to set exponentiation with a base of ordinal 2. Proposition 10.44 of [TakeutiZaring] p. 96. (This proof seems excessively long. An attempt to find a shorter one is on my to-do list.)
|- A e. V   =>   |- P~A ~~ (2o ^m A)
 
Schroeder-Bernstein Theorem
 
Theoremsbthlem1 4434 Lemma for sbth 4444.
 
Theoremsbthlem2 4435 Lemma for sbth 4444.
 
Theoremsbthlem3 4436 Lemma for sbth 4444.
 
Theoremsbthlem4 4437 Lemma for sbth 4444.
 
Theoremsbthlem5 4438 Lemma for sbth 4444.
 
Theoremsbthlem6 4439 Lemma for sbth 4444.
 
Theoremsbthlem7 4440 Lemma for sbth 4444.
 
Theoremsbthlem8 4441 Lemma for sbth 4444.
 
Theoremsbthlem9 4442 Lemma for sbth 4444.
 
Theoremsbthlem10 4443 Lemma for sbth 4444.
 
Theoremsbth 4444 Schroeder-Bernstein Theorem. Theorem 18 of [Suppes] p. 95. This theorem states that if set A is smaller (has lower cardinality) than B and vice-versa, then A and B are equinumerous (have the same cardinality). The interesting thing is that this can be proved without invoking the Axiom of Choice, as we do here, but the proof as you can see is quite difficult. (The theorem can be proved more easily if we allow AC.) The main proof consists of lemmas sbthlem1 4434 through sbthlem10 4443; this final piece mainly changes bound variables to eliminate the hypotheses of sbthlem10 4443. We follow closely the proof in Suppes, which you should consult to understand our proof at a higher level.
|- ((A ~<_ B /\ B ~<_ A) -> A ~~ B)
 
Theoremsbthbg 4445 Schroeder-Bernstein Theorem and its converse.
|- (B e. C -> ((A ~<_ B /\ B ~<_ A) <-> A ~~ B))
 
Theoremsbthcl 4446 Schroeder-Bernstein Theorem in class form.
|- ~~ = ( ~<_ i^i `' ~<_ )
 
Theoremdfsdom2 4447 Alternate definition of strict dominance. Compare Definition 3 of [Suppes] p. 97.
|- ~< = ( ~<_ \ `' ~<_ )
 
Theorembrsdom2 4448 Alternate definition of strict dominance. Definition 3 of [Suppes] p. 97.
|- A e. V   &   |- B e. V   =>   |- (A ~< B <-> (A ~<_ B /\ -. B ~<_ A))
 
Theoremsdomnsym 4449 Strict dominance is not symmetric. Theorem 21(ii) of [Suppes] p. 97.
|- (A ~< B -> -. B ~< A)
 
Theoremdomnsym 4450 Theorem 22(i) of [Suppes] p. 97.
|- (A ~<_ B -> -. B ~< A)
 
Theorem0dom 4451 Any set dominates the empty set.
|- (/) ~<_ A
 
Theoremdom0 4452 A set dominated by the empty set is empty.
|- (A ~<_ (/) <-> A = (/))
 
Theorem0sdomg 4453 A set strictly dominates the empty set iff it is not empty.
|- (A e. B -> ((/) ~< A <-> A =/= (/)))
 
Theorem0sdom 4454 A set strictly dominates the empty set iff it is not empty.
|- A e. V   =>   |- ((/) ~< A <-> A =/= (/))
 
Theoremsdom0 4455 The empty set does not strictly dominate any set.
|- -. A ~< (/)
 
Theoremsdomdomtr 4456 Transitivity of strict dominance and dominance. Theorem 22(iii) of [Suppes] p. 97.
|- (C e. D -> ((A ~< B /\ B ~<_ C) -> A ~< C))
 
Theoremsdomentr 4457 Transitivity of strict dominance and equinumerosity. Exercise 11 of [Suppes] p. 98.
|- (C e. D -> ((A ~< B /\ B ~~ C) -> A ~< C))
 
Theoremensdomtr 4458 Transitivity of equinumerosity and strict dominance.
|- ((A ~~ B /\ B ~< C) -> A ~< C)
 
Theoremsdomirr 4459 Strict dominance is irreflexive. Theorem 21(i) of [Suppes] p. 97.
|- -. A ~< A
 
Theoremsdomex 4460 Technical lemma for simplifying proofs involving strict dominance.
|- (A ~< B -> (A e. V /\ B e. V))
 
Theoremsdomtr 4461 Strict dominance is transitive. Theorem 21(iii) of [Suppes] p. 97.
|- ((A ~< B /\ B ~< C) -> A ~< C)
 
Theoremsdomn2lp 4462 Strict dominance has no 2-cycle loops.
|- -. (A ~< B /\ B ~< A)
 
Theoremdomsdomtr 4463 Transitivity of dominance and strict dominance. Theorem 22(ii) of [Suppes] p. 97.
|- ((A ~<_ B /\ B ~< C) -> A ~< C)
 
Theoremenen1 4464 Equality-like theorem for equinumerosity.
|- ((B e. D /\ A ~~ B) -> (A ~~ C <-> B ~~ C))
 
Theoremenen2 4465 Equality-like theorem for equinumerosity.
|- ((B e. D /\ A ~~ B) -> (C ~~ A <-> C ~~ B))
 
Theoremdomen1 4466 Equality-like theorem for equinumerosity and dominance.
|- ((B e. D /\ A ~~ B) -> (A ~<_ C <-> B ~<_ C))
 
Theoremdomen2 4467 Equality-like theorem for equinumerosity and dominance.
|- ((B e. D /\ A ~~ B) -> (C ~<_ A <-> C ~<_ B))
 
Theoremsdomen1 4468 Equality-like theorem for equinumerosity and strict dominance.
|- ((B e. D /\ A ~~ B) -> (A ~< C <-> B ~< C))
 
Theoremsdomen2 4469 Equality-like theorem for equinumerosity and strict dominance.
|- ((B e. D /\ A ~~ B) -> (C ~< A <-> C ~< B))
 
Theoremfodomr 4470 There exists a mapping from a set onto any (non-empty) set that it dominates.
|- ((A e. C /\ (/) ~< B /\ B ~<_ A) -> E.f f:A-onto->B)
 
Theoremcanth2 4471 Cantor's Theorem. No set is equinumerous to its power set. Specifically, any set has a cardinality (size) strictly less than the cardinality of its power set. For example, the cardinality of real numbers is the same as the cardinality of the power set of integers, so real numbers cannot be put into a one-to-one correspondence with integers. Theorem 23 of [Suppes] p. 97. For the function version, see canth 3899.
|- A e. V   =>   |- A ~< P~A
 
Theoremcanth2g 4472 Cantor's theorem with the sethood requirement expressed as an antecedent. Theorem 23 of [Suppes] p. 97.
|- (A e. B -> A ~< P~A)
 
Theorempwuninel 4473 The power set of the union of a set does not belong to the set. This theorem provides a way of constructing a new set that doesn't belong to a given set.
|- -. P~U.A e. A
 
Theorem2pwuninel 4474 The power set of the power set of the union of a set does not belong to the set. This theorem provides a way of constructing a new set that doesn't belong to a given set.
|- -. P~P~U.A e. A
 
Theoremxpen 4475 Equinumerosity law for cross product. Proposition 4.22(b) of [Mendelson] p. 254.
|- A e. V   &   |- B e. V   &   |- C e. V   &   |- D e. V   =>   |- ((A ~~ B /\ C ~~ D) -> (A X. C) ~~ (B X. D))
 
Theoremmapenlem1 4476 Lemma for mapen 4478.
 
Theoremmapenlem2 4477 Lemma for mapen 4478.
 
Theoremmapen 4478 Two set exponentiations are equinumerous when their bases and exponents are equinumerous. Theorem 6H(c) of [Enderton] p. 139.
|- A e. V   &   |- B e. V   &   |- C e. V   &   |- D e. V   =>   |- ((A ~~ B /\ C ~~ D) -> (A ^m C) ~~ (B ^m D))
 
Theoremmapdom1 4479 Order-preserving property of set exponentiation. Theorem 6L(c) of [Enderton] p. 149.
|- A e. V   &   |- B e. V   &   |- C e. V   =>   |- (A ~<_ B -> (A ^m C) ~<_ (B ^m C))
 
Theoremmapdom2lem 4480 Lemma for mapdom2 4481.
 
Theoremmapdom2 4481 Order-preserving property of set exponentiation. Theorem 6L(d) of [Enderton] p. 149.
|- A e. V   &   |- B e. V   &   |- C e. V   =>   |- ((A ~<_ B /\ -. (A = (/) /\ C = (/))) -> (C ^m A) ~<_ (C ^m B))
 
Theoremmapxpen 4482 Equinumerosity law for double set exponentiation. Proposition 10.45 of [TakeutiZaring] p. 96.
|-