HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
Unicode version

Theorem ineqan12d 2215
Description: Equality deduction for intersection of two classes.
Hypotheses
Ref Expression
ineq1d.1 |- (ph -> A = B)
ineqan12d.2 |- (ps -> C = D)
Assertion
Ref Expression
ineqan12d |- ((ph /\ ps) -> (A i^i C) = (B i^i D))

Proof of Theorem ineqan12d
StepHypRef Expression
1 ineq12 2208 . 2 |- ((A = B /\ C = D) -> (A i^i C) = (B i^i D))
2 ineq1d.1 . 2 |- (ph -> A = B)
3 ineqan12d.2 . 2 |- (ps -> C = D)
41, 2, 3syl2an 454 1 |- ((ph /\ ps) -> (A i^i C) = (B i^i D))
Colors of variables: wff set class
Syntax hints:   -> wi 3   /\ wa 223   = wceq 954   i^i cin 2042
This theorem is referenced by:  iooint 6317  fh1t 9501
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 960  ax-gen 961  ax-8 962  ax-10 964  ax-12 966  ax-17 969  ax-4 971  ax-5o 973  ax-6o 976  ax-9o 1121  ax-10o 1138  ax-16 1208  ax-11o 1216  ax-ext 1457
This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 979  df-sb 1170  df-clab 1462  df-cleq 1467  df-clel 1470  df-v 1808  df-in 2047
Copyright terms: Public domain