Theorem hba2 1015

Description: Lemma 24 of [Monk2] p. 114.

Assertion

Ref	Expression
hba2	|- (A.yA.xph -> A.xA.yA.xph)

Proof of Theorem hba2

Step	Hyp	Ref	Expression
1		hba1 1005	. 2 |- (A.xph -> A.xA.xph)
2	1	hbal 1007	1 |- (A.yA.xph -> A.xA.yA.xph)

Syntax hints:   -> wi 3  A.wal 956

This theorem is referenced by:  fnoprabg 4018  axacndlem4 4974  axacnd 4976

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-mp 7  ax-7 964  ax-gen 965  ax-4 975  ax-5o 977

Copyright terms: Public domain