Theorem fnrel 3592

Description: A function with domain is a relation.

Assertion

Ref	Expression
fnrel	|- (F Fn A -> Rel F)

Proof of Theorem fnrel

Step	Hyp	Ref	Expression
1		fnfun 3591	. 2 |- (F Fn A -> Fun F)
2		funrel 3539	. 2 |- (Fun F -> Rel F)
3	1, 2	syl 10	1 |- (F Fn A -> Rel F)

Syntax hints:   -> wi 3  Rel wrel 3181  Fun wfun 3182   Fn wfn 3183

This theorem is referenced by:  fnbr 3596  fnresdm 3602  fn0 3611  fnex 3613  frel 3636  fcoi1 3651  fnopabfv 3764  fnsnfv 3773  eqfnfv 3803  fconst5 3854  tz7.48-2 3963

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7

This theorem depends on definitions:  df-bi 147  df-an 225  df-fun 3198  df-fn 3199

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