Theorem fnop 3597

Description: The first argument of an ordered pair in a function belongs to the function's domain.

Assertion

Ref	Expression
fnop	|- ((F Fn A /\ <.B, C>. e. F) -> B e. A)

Proof of Theorem fnop

Step	Hyp	Ref	Expression
1		fnbr 3596	. 2 |- ((F Fn A /\ BFC) -> B e. A)
2		df-br 2625	. 2 |- (BFC <-> <.B, C>. e. F)
3	1, 2	sylan2br 455	1 |- ((F Fn A /\ <.B, C>. e. F) -> B e. A)

Syntax hints:   -> wi 3   /\ wa 223   e. wcel 960  <.cop 2415   class class class wbr 2624   Fn wfn 3183

This theorem is referenced by:  2elresin 3604  fcoi1 3651  fnopabfv 3764  tfrlem2 3918  tfrlem9 3925

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-10 968  ax-11 969  ax-12 970  ax-13 971  ax-14 972  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-16 1212  ax-11o 1220  ax-ext 1462  ax-sep 2708  ax-pow 2748  ax-pr 2785

This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 983  df-sb 1174  df-eu 1384  df-mo 1385  df-clab 1467  df-cleq 1472  df-clel 1475  df-ne 1590  df-v 1815  df-dif 2052  df-un 2053  df-in 2054  df-ss 2056  df-nul 2284  df-pw 2406  df-sn 2416  df-pr 2417  df-op 2420  df-br 2625  df-opab 2672  df-xp 3190  df-rel 3191  df-dm 3194  df-fun 3198  df-fn 3199

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