Theorem equtr 1130

Description: A transitive law for equality.

Assertion

Ref	Expression
equtr	|- (x = y -> (y = z -> x = z))

Proof of Theorem equtr

Step	Hyp	Ref	Expression
1		ax-8 963	. 2 |- (y = x -> (y = z -> x = z))
2	1	equcoms 1129	1 |- (x = y -> (y = z -> x = z))

Syntax hints:   -> wi 3   = wceq 955

This theorem is referenced by:  equtrr 1131  equtr2 1132  equequ1 1133  equvin 1274  a12lem1 1375  axsep 2698  dscmet 7880

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 962  ax-8 963  ax-12 967  ax-4 972  ax-5o 974  ax-6o 977  ax-9o 1122

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