Theorem ancom13s 488

Description: Deduction rearranging conjuncts.

Hypothesis

Ref	Expression
an1s.1	|- ((ph /\ (ps /\ ch)) -> th)

Assertion

Ref	Expression
ancom13s	|- ((ch /\ (ps /\ ph)) -> th)

Proof of Theorem ancom13s

Step	Hyp	Ref	Expression
1		an1s.1	. . . 4 |- ((ph /\ (ps /\ ch)) -> th)
2	1	exp32 377	. . 3 |- (ph -> (ps -> (ch -> th)))
3	2	com13 33	. 2 |- (ch -> (ps -> (ph -> th)))
4	3	imp32 363	1 |- ((ch /\ (ps /\ ph)) -> th)

Syntax hints:   -> wi 3   /\ wa 223

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7

This theorem depends on definitions:  df-bi 147  df-an 225

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