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Theorem 3mix2 816
Description: Introduction in triple disjunction.
Assertion
Ref Expression
3mix2 |- (ph -> (ps \/ ph \/ ch))

Proof of Theorem 3mix2
StepHypRef Expression
1 3mix1 815 . 2 |- (ph -> (ph \/ ch \/ ps))
2 3orrot 781 . 2 |- ((ps \/ ph \/ ch) <-> (ph \/ ch \/ ps))
31, 2sylibr 200 1 |- (ph -> (ps \/ ph \/ ch))
Colors of variables: wff set class
Syntax hints:   -> wi 3   \/ w3o 774
This theorem is referenced by:  tz7.44-2 3929
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7
This theorem depends on definitions:  df-bi 147  df-or 224  df-3or 776
Copyright terms: Public domain